(51+52.+99+100)-(1+2+3+.+49+50)怎么做
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(51+52.+99+100)-(1+2+3+.+49+50)怎么做
用前一个数加后一个数也就和、
(51+52.+99+100)-(1+2+3+.+49+50)
=(50+1+50+2+50+3...+50+50)-(1+2+3+...+49+50)
=50*50+1+2+3+...+50-(1+2+3+...+49+50)
=2500
(51+52.......+99+100)-(1+2+3+......+49+50)
=(51-1)+(52-2)+......+(99-49)+(100-50)
=50+50+.....+50 - - - - - - -- -- 共50个50
=2500
(51+52.......+99+100)-(1+2+3+......+49+50)
=(50+1+50+2+50+3...+50+50)-(1+2+3+...+49+50)
=50*50+1+2+3+...+50-(1+2+3+...+49+50)
=2500
(51+52.......+99+100)-(1+2+3+......+49+50)
=(50+1+50+2+50+3...+50+50)-(1+2+3+...+49+50)
=50*50+1+2+3+...+50-(1+2+3+...+49+50)
=2500
(51+52.......+99+100)-(1+2+3+......+49+50)
=(50+1+50+2+50+3...+50+50)-(1+2+3+...+49+50)
=2500
(50+51+52.+99+100)-(1+2+3.+59+58)
(51+52.+99+100)-(1+2+3+.+49+50)怎么做
计算下列数字方阵中的所有数的和 1 2 3 ...48 49 50 2 3 4 ...49 50 51 3 4 5 ...50 51 52 50 51 52...99
1/50*51+1/51*52+.+1/99*100
100^3+99^3/100^3+1^+99^3+97^3/99^3+2^3……+51^3+1^/51^3+50^3
(100+99*1)+(99+99*2)+(98+99*3)+...+(2+99*99)+(1+99*100)
1*100+2*99+3*98+4*97+(省略号)+50*51
1*100+2*99+3*98+4*97+5*96+.+50*51=?,要有过程的、、、
1+2+.+99+100
100+100-99-2+1
100^3+99^3/100^3+1^+99^3+97^3/99^3+2^3……+51^3+1^/51^3+50^3=?(100^3+99^3)/(100^3+1^3)+(99^3+97^3)/(99^3+2^3)+……+(51^3+1^3)/(51^3+50^3)=?规律是 (m^3+(m-n)^3)/(m^3+n^3)=(m+(m-n))/(m+n)例子 (
2*(100+99+98+97+...+51)-(1+2+3+4+5+...+50)等于多少,要有过程
【1/(1*2)+1/(3*4)+1/(5*6)+1/(7*8)+……1/(99*100)】/(1/51+1/52+……1/100)如何巧算呀?
(1/1*2+1/3*4+1/5*6+1/7*8+...+1/99*100)/(1/51+1/52+...+1/100)
(1)计算1/1*2+1/2*3+1/3+4.+1/99*100 (2)1/1*3+1/3*5+1/5*7.+1/49*51
小学六年级思维能力拓展题:下下面数字方阵中共有25000个数,所有这些数之和等于多少?1 2 3 … 49 502 3 4 … 50 513 4 5 … 51 52...............50 51 52 98 99是2500个数
一道数学首项末项计算题(1+3+5+7+ ...+99+101)-(2+4+6+8+ ...+98+100)正确答案是51
1-1/2+1/3-1/4+1/5-1/6…+1/99-1/100)/(1/51+1/52+1/53+…+1/99+1/100)=?