0.12+0.23+0.34+0.45+0.56+0.67+0.78+0.89=?

(0.12+0.23+0.34)×(0.23+0.34+0.45)-(0.12+0.23+0.34+0.45)×(0.23+0.34) （0.12+0.23+0.34）*（0.23+0.34+0.45）-（0.12+0.23+0.34+0.45）*（032+034）简便计算 0.12+0.23+0.34+0.45+0.56+0.67+0.78+0.89=? (1+0.23+0.34)*(0.23+0.34+0.45)-(1+0.23+0.34+0.45)*(0.23+0.34)简便运算 （1+0.23+0.34）×（0.23+0.34+0.45）-（1+0.23+0.34+0.45）×（0.23+0.34） 0.12+0.23+0.34+0.45+0.56注意!都是循环的,例如0.12的12循环,0.23的23循环 求解(1+0.12+0.23)*(0.12+0.23+0.34)-(1+0.12+0.23+0.34)*(0.12+0.23)=? 简便运算 (1+0.12+0.23)x(0.12+0.23+0.34)-(1+0.12+0.23+0.34)x(0.12+0.23) (1+0.12+0.23)*(0.12+0.23+0.34)-(1+0.12+0.23+0.34)*(0.12+0.23)= （1+0.12+0.23）×（0.12+0.23+0.34）- （1+0.12+0.23+0.34）×（0.12+0.23）. (1+0.12+0.23)X(0.12+0.23+0.34)-(1+0.12+0.23+0.34)X(0.12+0.23)=? (1+0.12+0.23)乘(0.12+0.23+0.34)_(1+0.12+0.23+0.34)乘(0.12+0.23) 0.12+0.23+0.34+0.45+0.56+0.67+0.78注意是循环小数,循环节在第二位 0.12+0.23+0.34+0.45+0.56答案是几 注：都是循环小数,第二位开始 0.12+0.23+0.34+0.45+0.56+0.67+0.78注意是循环小数,循环节在第二位 《2》 简便运算（1+0.12+0.23）X(0.12+0.23+0.34) - (1+0.12+0.34)X(0.12+0.23) （0.12＋0.23＋0.34）*（0.23＋0.34＋0.45）－（0.12＋0.23＋0.34＋0.45）这是题目,看我打字辛苦的份上帮帮我 (1+0.12+0.23)x(0.12+0.23+0.34)-(1+0.12+0.23+0.34)x(0.12+0.23)等于几?用简便方法计算!