设a,b,c均为正实数,求证1/2a+1/2b+1/2c大于等于1/(b+c)+1/(c+a)+1/(a+b)

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设a,b,c均为正实数,求证1/2a+1/2b+1/2c大于等于1/(b+c)+1/(c+a)+1/(a+b)

证明:∵1/x+1/y>-4/(x+y)=(x+y)/(xy)-4/(x+y)
=[(x+y)^2-4xy]/[(xy)(x+y)]
=(x-y)^2/[(xy)(x+y)]
当x>0,y>0时 (x-y)^2/[(xy)(x+y)]>=0
∴1/(4x)+1/(4y)>=1/(x+y)
从而 1/2a+1/2b+1/2c=1/4a+1/4b+1/4b+1/4c+1/4c+1/4a
>=1/(a+b)+1/(b+c)+1/(c+a)
∴1/2a+1/2b+1/2c大于等于1/(b+c)+1/(c+a)+1/(a+b)