设a,b,c均为正实数,求证:1/2a+1/2b+1/2c》1/(b+c)+1/(c+a)+1/(a+b)

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设a,b,c均为正实数,求证:1/2a+1/2b+1/2c》1/(b+c)+1/(c+a)+1/(a+b)

1/a+1/b+1/c=(a+b)/2ab+(b+c)/2bc+(a+c)/2ac>=1/根号ab+1/根号bc+1/根号ca>=2/(a+b)+2/(b+c)+2/(c+a)
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