已知|a-1|+(b+4)^2=0,求[(2a+b)^2-(2a+b)(2a-b)-6b]÷2b的值谢

来源:学生作业学帮网 编辑:学帮网 时间:2024/06/26 03:49:54

已知|a-1|+(b+4)^2=0,求[(2a+b)^2-(2a+b)(2a-b)-6b]÷2b的值

|a-1|+(b+4)^2=0
|a-1|=0
a=1
(b+4)^2=0
b=-4
[(2a+b)^2-(2a+b)(2a-b)-6b]÷2b
=[(2a+b)(2a+b-2a+b)-6b]÷2b
=[(2a+b)*(2b)-6b]÷2b
=2b[(2a+b)-3]÷2b
=(2a+b)-3
=2a+b-3
=2*1-4-3
=2-7
=-5