lim[x→0](x^3-3x^2+6x-2)/(2x^3+x^2)=?同问

lim(x→0) (3x^2-5x+2), lim(x→0)2x^3-x+1 lim (x^3-x^2+4x)/(x^2+x) x→ 0 求lim(x→0)x cos 1/x lim(x→∞)x^2/ (3x-1)的极限 lim(x→0)×(x-sin²3x)/x lim(x->0)((2-x)/(3-x))^1/x 1、lim(x->无穷大) e^x arctanx2、lim(x->0)sinx√1+sin(1/x)3、lim(x->无穷大)【（√x^2+x+1）-【(√x^2-x+1)】4、lim(x->无穷大)((x+{x+(x)^0.5]^0.5}^0.5)/(2x+1)^0.55、lim(x->0)(sin3x+x^2sin1/x)/((1+cosx)x)6、lim(n->无穷大)(2^n)(si 烦人的数学微积分1、lim(x→0)Sin3x/Sin2x2、lim(x→0)x/3*Sin3x3、lim(x→0)[Xsin(3/x)+(tanx/2x)]4、lim(x→3)Sin(x-3)/(X^2-X-6)5、lim(x→∞)[1+(1/2x)^x6、lim(x→∞)(x+3/x)^x7、lim(x→0)（1-x/2)^1/x+118、求下列函数的间断 lim[x→0](x^3-3x^2+6x-2)/(2x^3+x^2)=?同问 lim (x->0) 3x/(sinx-x) 已知lim x→0 [sin6x+xf(x)]/x^3=0,求 lim x→0 [6+f(x)]/x^2?为什么不可以这样解 因为lim x→0 [sin6x/(6x)]=1所以,lim x→0 [sin6x+xf(x)]/x^3=lim x→0 [6x+xf(x)]/x^3=lim x→0 [6+f(x)]/x^2=0这哪里错了? lim x→0 (x^2+2x-1)/(x^3-2x)的极限是多少 lim(x→0)[tan(2x+x^3)/sin(x-x^2)] lim (3x^2+4x+6)/(x^2+x) x→无限 lim(x→0)[(1+X)(1+2X)(1+3x)-1]/x lim(X->0)(7x^6+2x-1)/(2x^6+x+3)=? 设lim（x→0）[f(x)-3]/x^2=100,求lim(x→0)f(x) lim x→0 [sin6x+xf(x)]/x^3=0,求 lim x→0 [6+f(x)]/x^2