化简[1-(sin^4x-sin^2cos^2x+cos^4x)/(sin^2)]+3sin^2x

化简[1-(sin^4 x-sin^2 xcos^2 x+cos^4 x)]/(sin^2 x)+3sin^2 x 化简[1-(sin^4x-sin^2cos^2x+cos^4x)/(sin^2)]+3sin^2x 傅里叶级数作图f（x）=2sin[x] - sin[2x] + 2/3sin[3x] - 1/2sin[4x]我用mathematica输入程序Plot[{2sin[x],-2sin[x],2sin[x] - sin[2x],-2sin[x] + sin[2x],2sin[x] - sin[2x] + 2/3sin[3x],-2sin[x] + sin[2x] - 2/3sin[3x],2sin[x] - sin[2x] + 2/3si 化简sin^4x-sin^2x+cos^2x 化简:sin^4 x-sin^2 x+cos^2 x 化简(sin x+cos x-1)(sin x-cos x+1)/sin 2x (1-(sin^4x-sin^2xcos^2x+cos^4x)/sin^2x +3sin^2x 化简(sin^2 x/sin x-cosx)-(sin x+cosx/tan^2 x-1) 化简2sin^2[(π/4)+x]+根号3（sin^x-cos^x）-1 s = 2*sin(x)-sin(2*x)+2/3*sin(3*x)-1/2*sin(4*x)+2/5*sin(5*x)用matlab画图,求教啊 化简sin(-2x) 证明一个sin&cos的等式证明 1+sin^2(x)+sin^4(x)+sin^6(x)=[1-sin^8(x)]/[cos^2(x)] 化简sin^4x+cos^2x 化简(sin^2x-cos^4x+cos^2x-sin^4x)/(sin^2x-cos^6x+cos^2x-sin^6x) 求证:(sin 2x /(1-cos 2x) )·(sin x /(1+sin x))=tan (π/4-x/2). 求证（cos^2 x-sin^2 x)(cos^4 x+sin^4 x)+1/4 sin 2x sin 4x=cos 2x cos x/sin x+sin x/(1+cos x) 化简. 化简：1.根号下(1-sin^2)2.(1-cos^4x-sin^4x)/(1-cos^6x-sin^6x)