A straight plam tree fell against another tree,forming a right triangle.The trunks of the two trees were 20 feet apart at the ground .A monkey climbs 53 feet up the learning tree trunk and then comes down the standing tree trunk.How many feet does th
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A straight plam tree fell against another tree,forming a right triangle.The trunks of the two trees were 20 feet apart at the ground .A monkey climbs 53 feet up the learning tree trunk and then comes down the standing tree trunk.How many feet does the monkey climb in coming down the vertical trunk in order to reach the ground
这道题翻译如下:
一棵笔直的棕榈树倒在另一棵树上,形成一个直角三角形.两颗树干在地面上的距离是20英尺,一只猴子在倒下的树干上(这里你是不是打错了,不是learning 是leaning)爬了53英尺,然后从笔直站立的树干上下来.那只猴子要向下爬多少英尺才能到达地面?
就是一个勾股的问题嘛~
53*2-20*2(*2 表示平方)然后开根号,自己开一下喽,我手别没计算器不好意思~
53^2-20^2=(53+20)*(53-20)=73*33=2409
斜边53的平方减去底边20的平方再开方,得出的数就是直角边,即结果。数学符号我写不好,希望你能明白 。
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