用分解因式法解下列方程 (x-1)2=(x-1)

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用分解因式法解下列方程 (x-1)2=(x-1)

(x-1)²=x-1
(x-1)²-(x-1)=0
(x-1)×(x-1-1)=0
(x-1)×(x-2)=0
x-1=0或者x-2=0
x=1或者2

(x-1)2=(x-1)
(x-1)^2-(x-1)=0
(x-1)(x-1-1)=0
(x-1)(x-2)=0
x=1或x=2

(x-1)²-(x-1)=0;
(x-1)(x-1-1)=0;
(x-1)(x-2)=0;
x=1或x=2;
有问题请追问~~