y=-(1.05+0.15x)^(-1), y=-(1.05-0.12x)^(-1) , 分别求dy/dx

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y=-(1.05+0.15x)^(-1),y=-(1.05-0.12x)^(-1) ,分别求dy/dx
①dy/dx=(-(1.05+0.15x)^(-1))′=-(1.05+0.15x)^(-1)*(1.05+0.15x)′
=-(1.05+0.15x)^(-1)*0.15
=-1/(7+x)
②dy/dx=(-(1.05-0.12x)^(-1))′=-(1.05-0.12x)^(-1)*(1.05-0.12x)′
=-(1.05-0.12x)^(-1)*(-0.12)
=1/(8.75-x)

y=e^(x) dy/dx=e^(x)
所以 y=〖-e〗^(1.05+0.15A), dy/dx=-0.15e^(1.05+0.15x)
y=〖-e〗^(1.05-0.12A), dy/dx=0.12e^(1.05-0.12x)

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