求解```y=log(2+√3)(2sinx-√3)的定义域和值域

log(2x)+log(3y)-log(2z) 怎么化简?log3(x^2-2x-6)=2 log(3x+6)=1+log(x)求解,求每步详...log(2x)+log(3y)-log(2z) 怎么化简?log3(x^2-2x-6)=2 log(3x+6)=1+log(x)求解, 求解```y=log(2+√3)(2sinx-√3)的定义域和值域 log(2x)+log(3y)-log(2z) 怎么化简? log3(x^2-2x-6)=2 log(3x+6)=1+log(x)求解. 已知log（2）[log（3)(log(4) x)] = log(3) [log(4) (log(2) y)]=0,求x+y的值 log(2)(x-1)=log(2)(x2+2x-3)求解!要步骤!谢谢 log底数3[log底数4(log底数2y)]=0等于多少? 若log底数2[log底数3(log底数4)]若log底数2[log底数3(log底数4（x）)]=log底数3[log底数4(log底数2(y))]=log底数4[log底数2(log底数3z)]=0,则x+y+z= log 9 X/Y=1/2(log 3 X - log 3 Y) log 9 X/Y=1/4 3log 3 X =2log 3 Y find X and Y log(4)y+log(2y)=9怎么解 [log(4)(2x)][log(2x)(3y)][log(3y)(z)]=log(8x)[(8x)]^2,则z=? 用C语言计算log(5)log(3)-log(2))/sin(π/3)=#include #includeint main(){int a=5,b=3,c=2;double y;y=(log(a)log(b)-log(c))/sin(π/b);printf((log(5)log(3)-log(2))/sin(π/3)=%ld,y);return 0;}x这哪里错了? 函数y=log(1/2)2x+log(1/3)x的单调区间为 y=log2(sinx+3)的值域log后的2在log下面 2log(m)y-log(m)x-log(m)z 求解一道log题log8（x+1）=2/3 求x log(3)4*log(4)8*log(8)M =log(2)16 M是多少呃.... 求等式log(2)3*log(3)4*log（4)5*log(5)6*log(6)7*log(7)m=log(3)9时m的值? log 3 (4+x+4y)^2=0 联立 log 2 (x+1)^2=1+3log 2 y^2 求