4(x-3)的平方+x(x-3)=0

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4(x-3)的平方+x(x-3)=0

(4x-12)(x-3)+x(x-3)=0
(5x-12)(x-3)=0
x1=3
x2=12/5

(x-3)(4x-12)+x(x-3)=0
(x-3)(4x-12+x)=0
(x-3)(5x-12)=0
x=3,x=2.4

5x^2-27x+36=0.
(x-3)*(5x-12)=0.
x=3或x=12/5.