1.With their bare hands,they fought to save the man who was seriously hurt in the attack.2.三角函数:sin(60°-x)cos(x-20°)+cos(65°-x)cos(110°-x)的值为( )A.√2 B.(√2)／2 C.1／2 D.(√3)／2请写出具体过程

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1.
With their bare hands,they fought to save the man who was seriously hurt in the attack.
2.三角函数:
sin(60°-x)cos(x-20°)+cos(65°-x)cos(110°-x)的值为( )
A.√2 B.(√2)／2 C.1／2 D.(√3)／2
请写出具体过程

1.他们赤手空拳地拼着命,就是为了挽救那个在战斗中严重受伤的男人.
2.sin(65°-x)cos(x-20°)+cos(65°-x)cos(110°-x)=sin(65°-x)cos(x-20°)+cos(65°-x)sin(x-20°)
=sin[(65°-x)+(x-20°)]=sin45°=根号2 /2

问题不是很简单的话， 一般有悬赏比较好。
他们赤手空拳拼命挽救那个在战斗中严重受伤的男人。
第二道题题目可能写错了 前面那部分应该都是sin
这样结果就是B。

用他们赤裸的双手，他们奋勇抢救在袭击中受伤很严重的男子

他们赤手空拳地，救出了在战争中严重受伤的男人。

B

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