设z=uv,u=e^(x+y),v=ln(xy)求dy

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设z=uv,u=e^(x+y),v=ln(xy)求dy

dy/dx=dy/du *du/dx+dy/dv*dv/dx
=v*e^(x+y)+u*y/x
=ln(xy) *e^(x+y)+e^(x+y)*y/x
=e^(x+y)[ln(xy)+y/x]
所以dy=e^(x+y)[ln(xy)+y/x]dx