计算:(a-1)分之(2a+2)÷(a+1)-(a的平方-2a+1)分之(a的平方-1)

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计算:(a-1)分之(2a+2)÷(a+1)-(a的平方-2a+1)分之(a的平方-1)

=2(a+1)/(a-1)×1/(a+1)-(a+1)(a-1)/(a-1)²
=2/(a-1)-(a+1)/(a-1)
=(2-a-1)/(a-1)
=(1-a)/(a-1)
=-1