∫sin^2xcos^2xdx

∫sin^3xcos^2xdx 

求不定积分∫sin^2*xcos^5*xdx∫(sinx)^2(cosx)^5dx=∫(sinx)^2(cosx)^4d(sinx)=∫(sinx)^2(1-(sinx)^2)^2d(sinx)=∫[(sinx)^6-2(sinx)^4+(

问高数求导∫sin^3xcos^2xdx∫sin^3xcos^2xdx=-∫sin^2xcos^2xdcosx=-∫(1-cos^2x)*cos^2xdcosx=-∫(cos^2x-cos^4x)dcosx=(1/5)*cos^5x-(1/

不定积分：∫xcos^2xdxcos^2x=(cos2x+1)/2∫xcos^2xdx=∫x(cos2x+1)dx/2+C=(∫xcos2xdx+∫xdx)/2+C=(∫xdsin2x+x^2)/4+C=(xsin2x-∫sin2xdx+x

不定积分：∫xcos^2xdx∫xcos^2xdx=∫x(1+cos2x/2)dx=1/2∫xdx+1/2∫xcos2xdx=x²/4+1/4∫xdsin2x=x²/4+1/4*xsin2x-1/4∫sin2xdx=x&

∫sin^3xcosxdx.原式=积分(sinx)^3d(sinx)=1/4*(sinx)^4+C

求不定积分1/sin^4xcos^2xdx

求定积分∫上限π/2,下限04sin^2xcos^2xdx,这题方法有很多,你可以把cos^2x换成1-sin^2x4sin^2xcos^2x=4(sin^2x-sin^4x)sin^2x和sin^4x积分是有公式的.但是一般人估计也记不得

∫sin^3xcos^2xdx第一步∫sin^2xcos^2x*sinxdx(这部看懂了）第二步∫（1-cos^2x)cos^2x*(-d(cosx))为什么sinx变成（-d(cosx))了?∫sin^3xcos^2xdx=-∫sin^2

∫sin^2xdx答：由cos2x=1-2(sinx)^2得：(sinx)^2=1/2-cos2x/2∫(sinx)^2dx=∫1/2-cos2x/2dx=x/2-sin2x/4+C

求不定积分∫sin^2*xcos^5*xdx∫(sinx)^2(cosx)^5dx=∫(sinx)^2(cosx)^4d(sinx)=∫(sinx)^2(1-(sinx)^2)^2d(sinx)=∫[(sinx)^6-2(sinx)^4+(

数学里三角函数积分问题∫sin^2xcos^2xdx类似这类题目该从哪入手∫sin²xcos²xdx=∫(1/4×sin²2x)dx=∫[1/8×(1-cos4x)]dx=x/8-1/8∫cos4xdx+C=x

∫二分之派为上限0为下限sin^2xcos^3xdx的定积分..

求下列不定积分∫(xcosx)/sin³xdx看图!-cotx/2-x/（2sin²x）+C过程太不好打了，就写了个结果

计算不定积分∫sin²xcos²xdx

∫x/sin^2xdx原式=∫xcsc^2(x)dx=-∫xd(cotx)=-xcotx+∫cotxdx=-xcotx+∫cosx/sinx*dx=-xcotx+∫d(sinx)/sinx=-xcotx+ln|sinx|+C

∫sin^2xdx=?∫sin^2xdx=∫（1-cos2x）/2dx=∫1/2dx-∫cos2x/2dx=x/2-1/4∫cos2xd(2x)=x/2-sin2x/4+C(C是常数）

∫1/(sin^2xcos^2x)∫1/(sin²xcos²x)dx=∫4/(4sin²xcos²x)dx=4∫1/sin²2xdx=2∫csc²2xd(2x)=-2cot2x+C

急求∫tan^(-1)(1/x)dx及∫sin^6xcos^2xdx详细解答,且要用到分部积分法的~∫arctan(1/x)dx=∫(x)'arctan(1/x)dx=xarctan(1/x)-∫x*{1/[1+x^(-2)]}*[-1/x

求不定积分∫xcosxdx∫cos²xdx=∫cosxdsinx=sinxcosx-∫sinxdcosx=sinxcosx+∫sin²xdx=sinxcosx+∫(1-cos²x)dx=sinxcosx+x-∫