sin^4xcos^xdx

∫sin^3xcosxdx.原式=积分(sinx)^3d(sinx)=1/4*(sinx)^4+C

求不定积分1/sin^4xcos^2xdx

∫sin^3xcos^2xdx 

求定积分∫上限π/2,下限04sin^2xcos^2xdx,这题方法有很多,你可以把cos^2x换成1-sin^2x4sin^2xcos^2x=4(sin^2x-sin^4x)sin^2x和sin^4x积分是有公式的.但是一般人估计也记不得

求不定积分∫sin^2*xcos^5*xdx∫(sinx)^2(cosx)^5dx=∫(sinx)^2(cosx)^4d(sinx)=∫(sinx)^2(1-(sinx)^2)^2d(sinx)=∫[(sinx)^6-2(sinx)^4+(

求下列不定积分∫(xcosx)/sin³xdx看图!-cotx/2-x/（2sin²x）+C过程太不好打了，就写了个结果

计算不定积分∫sin²xcos²xdx

问高数求导∫sin^3xcos^2xdx∫sin^3xcos^2xdx=-∫sin^2xcos^2xdcosx=-∫(1-cos^2x)*cos^2xdcosx=-∫(cos^2x-cos^4x)dcosx=(1/5)*cos^5x-(1/

∫sin^4xdx.降次计算即可原式=∫[(1-cos2x)/2]²dx=(1/4)∫(1-2cos2x+cos²2x)dx=x/4-(1/4)∫cos2xd(2x)+(1/4)∫[(1+cos4x)/2]dx=x/4-

∫sin^5xcos^3xdx怎么计算这一类的有什么方法没?∫sin^5xcos²xdsinx=∫sin^5x(1-sin²x)dsnx=∫(sin^5x-sin^7x)dsinx=1/6sin^6x-1/8sin^8x

不定积分：∫xcos^2xdxcos^2x=(cos2x+1)/2∫xcos^2xdx=∫x(cos2x+1)dx/2+C=(∫xcos2xdx+∫xdx)/2+C=(∫xdsin2x+x^2)/4+C=(xsin2x-∫sin2xdx+x

不定积分：∫xcos^2xdx∫xcos^2xdx=∫x(1+cos2x/2)dx=1/2∫xdx+1/2∫xcos2xdx=x²/4+1/4∫xdsin2x=x²/4+1/4*xsin2x-1/4∫sin2xdx=x&

求不定积分∫xcosxdx∫cos²xdx=∫cosxdsinx=sinxcosx-∫sinxdcosx=sinxcosx+∫sin²xdx=sinxcosx+∫(1-cos²x)dx=sinxcosx+x-∫

∫sin^3xcos^2xdx第一步∫sin^2xcos^2x*sinxdx(这部看懂了）第二步∫（1-cos^2x)cos^2x*(-d(cosx))为什么sinx变成（-d(cosx))了?∫sin^3xcos^2xdx=-∫sin^2

SIN^4XCOS^4XD的不定积分不定积分SIN^4XCOS^4XDX=1/16*S（sin2x)^4dx=1/64*S(1-cos4x)^2dx=1/64*S(1-2cos4x+(cos4x)^2)dx=1/64*(Sdx-S2cos4

1/(sin^4xcos^4x)积分

数学里三角函数积分问题∫sin^2xcos^2xdx类似这类题目该从哪入手∫sin²xcos²xdx=∫(1/4×sin²2x)dx=∫[1/8×(1-cos4x)]dx=x/8-1/8∫cos4xdx+C=x

若z=sin(xy)则它的全微分dz=A：xcos(xy)B：(xdx+ydy)cos(xy)C：ycos(xy)D：(ydx+xdy)cos(xy)dz=cos(xy)ydx+cos(xy)xdy=(ydx+xdy)cos(xy),选Dz

求不定积分∫sin^2*xcos^5*xdx∫(sinx)^2(cosx)^5dx=∫(sinx)^2(cosx)^4d(sinx)=∫(sinx)^2(1-(sinx)^2)^2d(sinx)=∫[(sinx)^6-2(sinx)^4+(

求不定积分∫(xcosx)/sin³xdx,这个解答里的第一步到第二步是怎么来的？我觉得第二步这样写不好,看我的做法∫xcosx/sin³xdx=∫x·cscx·cscxcotxdx,注意1/sinx=cscx,cosx