先化简,再求值:(x+y)^2-3x(x+3y)+2(x+2y)(x-2y),其中x=-1/3,y=1/3

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先化简,再求值:(x+y)^2-3x(x+3y)+2(x+2y)(x-2y),其中x=-1/3,y=1/3

:(x+y)^2-3x(x+3y)+2(x+2y)(x-2y)
=x²+2xy+y²-3x²-9xy+2x²-8y²
=-7xy-7y²
=-7y(x+y)
=-7×1/3×(-1/3+1/3)
=0

=xx+2xy+yy-3xx-9xy+2(xx-4yy)=-7xy-7yy=-7y(x+y)=0