学帮网求值：cosπ/17cos2π/17cos4π/17cos8π/17
来源：学生作业学帮网 编辑：学帮网 时间：2024/05/27 15:46:22
求值：cosπ/17cos2π/17cos4π/17cos8π/17
cos(π/17)cos(2π/17)cos(4π/17)cos(8π/17)
=[16sin(π/17)cos(π/17)cos(2π/17)cos(4π/17)cos(8π/17)]/16sin(π/17)
=[8sin(2π/17)cos(2π/17)cos(4π/17)cos(8π/17)]/16sin(π/17)
=[4sin(4π/17)cos(4π/17)cos(8π/17)]/16sin(π/17)
=[2sin(8π/17)cos(8π/17)]/16sin(π/17)
=sin(16π/17)/16sin(π/17)
=1/16
求值：cosπ/17cos2π/17cos4π/17cos8π/17
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cosπ/17cos2π/17cos4π/17cos8π/17=___
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