计算dy/dx

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计算dy/dx

y=x(x+1)^(1/2)*(x+2)^(-2)
y'=(x+1)^(1/2)*(x+2)^(-2)+(1/2)x(x+1)^(-1/2)*(x+2)^(-2)-2x(x+1)^(1/2)*(x+2)^(-3)
=(2-x)(x+2)^(-3)+(1/2)x(x+1)^(-1/2)*(x+2)^(-2)

wtf is the question? this equation means onthing.
dy/dx means the partial differential of x vs y. the answer could be an equation as well.

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