一道初二因式分解计算9(a+1)^2(a-1)^2-6(a^2-1)(b^2-1)+(b+1)^2(b-1)^2

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一道初二因式分解计算
9(a+1)^2(a-1)^2-6(a^2-1)(b^2-1)+(b+1)^2(b-1)^2

9(a+1)^2(a-1)^2-6(a^2-1)(b^2-1)+(b+1)^2(b-1)^2
=[3(a^2-1)]^2-6(a^2-1)(b^2-1)+(b^2-1)^2
=(3a^2-3)^2-6(a^2-1)(b^2-1)+(b^2-1)^2
=[(3a^2-3)-(b^2-1)]^2
=(3a^2-b^2-2)^2

9(a+1)^2(a-1)^2-6(a^2-1)(b^2-1)+(b+1)^2(b-1)^2
=9(a^2-1)^2-6(a^2-1)(b^2-1)+(b^2-1)^2
=(3(a^2-1)-(b^2-1))^2