2sin(2X+p)的导数怎么求

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2sin(2X+p)的导数怎么求

2*cos(2x+P)*2
=4*cos(2x+P)

2sin(2X+p)'
=2cos(2X+p)(2X+p)'
=2cos(2X+p)*2
=4cos(2X+P)

(2sin(2X+p))′=2cos(2x+p)×(2x+p)′=4cos(2x+p)

2sin(2X+p)。设2X+p=u。则2sin(2X+p)=2*sin(u)'*(2X+p)'=2*cos(2X+p)*2=4cos(2X+p)

2sin(2X+p)'=4cos(2x+p)