这两个计算题怎么算?1又1/2*5/7-(-5/7)*2又1/2+(-1/2)÷1又2/5-1^4-【1-(1-0.5*1/3)*6】

来源:学生作业学帮网 编辑:学帮网 时间:2024/05/19 17:00:43

这两个计算题怎么算?
1又1/2*5/7-(-5/7)*2又1/2+(-1/2)÷1又2/5
-1^4-【1-(1-0.5*1/3)*6】

1又1/2*5/7-(-5/7)*2又1/2+(-1/2)÷1又2/5
=(3/2)(5/7)-(-5/7)(5/2)+(-1/2)(5/7)
=(3/2)(5/7)+(-1/2)(5/7)-(-5/7)(5/2)
=(5/7)[(3/2)-(1/2)]-(-5/7)(5/2)
=(5/7)-(-5/7)(5/2)
=(5/7)[1+(5/2)]
=(5/7)(7/2)
=5/2
=2又1/2

-1^4-【1-(1-0.5*1/3)*6】
=-1-【1-(6-1)】
=-1-【1-6+1】
=-1+4
=3