人教版七年级数学练习册上的一道有理数乘法题(2+1/2003+1/2004+1/2005)*(1/2003+1/2004+1/2005+1/2006)-(2+1/2003+1/2004+1/2005+1/2006)*(1/2003+1/2004+1/2005).

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人教版七年级数学练习册上的一道有理数乘法题
(2+1/2003+1/2004+1/2005)*(1/2003+1/2004+1/2005+1/2006)-(2+1/2003+1/2004+1/2005+1/2006)*(1/2003+1/2004+1/2005).

令1/2003+1/2004+1/2005 =a
原式化为(2+a)*(a+1/2006)-(2+a+1/2006)*a
=2a+1/1003+a*a+1/2006*a-2a-a*a-1/2006*a
=1/1003

(2+1/2003+1/2004+1/2005)*(1/2003+1/2004+1/2005+1/2006)-(2+1/2003+1/2004+1/2005+1/2006)*(1/2003+1/2004+1/2005)
=2*(1/2003+1/2004+1/2005+1/2006)+(1/2003+1/2004+1/2005)*(1/2003+1/2004+1/2005+1/2006)-...

全部展开

(2+1/2003+1/2004+1/2005)*(1/2003+1/2004+1/2005+1/2006)-(2+1/2003+1/2004+1/2005+1/2006)*(1/2003+1/2004+1/2005)
=2*(1/2003+1/2004+1/2005+1/2006)+(1/2003+1/2004+1/2005)*(1/2003+1/2004+1/2005+1/2006)-2*(1/2003+1/2004+1/2005)-(1/2003+1/2004+1/2005+1/2006)*(1/2003+1/2004+1/2005)
=2*【(1/2003+1/2004+1/2005+1/2006)-(1/2003+1/2004+1/2005)】+
【(1/2003+1/2004+1/2005)*(1/2003+1/2004+1/2005+1/2006)-(1/2003+1/2004+1/2005+1/2006)*(1/2003+1/2004+1/2005)】
=2*1/2006
=1/1003

收起

分解因式啊,设a=1/2003+1/2004+1/2005;
b=1/2003+1/2004+1/2005+1/2006;
则原式化为 (2+a)*b-(2+b)*a=2*b-2*a=2(b-a)=1/1003