初二数学题2√2/(√3+√2)化简

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初二数学题2√2/(√3+√2)化简

2√2/(√3+√2)
=2√2*(√3-√2)/[(√3+√2)*(√3-√2)]
=2√2*(√3-√2)
=2√6-4

2√2/﹙√3+√2﹚=2√2﹙√3-√2﹚=2√6-4

上下同×√3-√2得2√6-4

2√2/(√3+√2)=[2√2(√3-√2)]/[(√3+√2﹚(√3-√2)]
=﹙2√6-4﹚/﹙3-2﹚
=2√6-4