化简(3+1)(3^2+1)(3^4+1)(3^8+1)得多少?希望说明步骤?^的意思是平方。也就是3的平方
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化简(3+1)(3^2+1)(3^4+1)(3^8+1)得多少?希望说明步骤?
^的意思是平方。也就是3的平方
^是什么符号?
先在原式上乘以(3-1)再除以(3-1) 分子利用平方差公式得 3^16-1 所以最后结果为(3^16-1)/2
(3+1)(3^2+1)(3^4+1)(3^8+1)
=(3-1)(3+1)(3^2+1)(3^4+1)(3^8+1)/(3-1)
=(3^2-1)(3^2+1)(3^4+1)(3^8+1)/(3-1)
=(3^4-1)(3^4+1)(3^8+1)/(3-1)
=(3^8-1)(3^8+1)/(3-1)
=(3^16-1)/2
(3+1)(3^2+1)(3^4+1)(3^8+1)
=(3+1))(3-1)(3^2+1)(3^4+1)(3^8+1)/(3-1)
=(3^2-1)(3^2+1)(3^4+1)(3^8+1)/(3-1)
=.....
(3+1)(3^2+1)(3^4+1)(3^8+1)
=(3-1)(3+1)(3^2+1)(3^4+1)(3^8+1)/(3-1)
=(3^2-1)(3^2+1)(3^4+1)(3^8+1)/(3-1)
=(3^4-1)(3^4+1)(3^8+1)/(3-1)
=(3^8-1)(3^8+1)/(3-1)
=(3^16-1)/2
先在原式上乘以(3-1)再除以(3-1) 分子利用平方差公式得 3^16-1 所以最后结果为(3^16-1)/2
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