cos60/1+sin60 +1/tan30

来源:学生作业学帮网 编辑:学帮网 时间:2024/05/20 16:21:18

cos60/1+sin60 +1/tan30

=(1/2)/(1+ √3/2)+1/(√3/3)
=1/(2+ √3) +√3
=2-√3+√3
=2

=1/(1/2)+根号3/2+1/(根号3/3)
=2+3*根号3/2


cos60/(1+sin60) +1/tan30
=1/2÷(1+√3/2)+1/(√3/3)
=1÷(2+√3)+√3
=1÷(2+√3)+√3(2+√3)÷(2+√3)
=(1+2√3+3)÷(2+√3)
=(4+2√3)÷(2+√3)
=2

感觉满意请采纳!如有疑问请追问!