函数f(X)=根号sin(-2x+π/3)的单调递增区间为

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函数f(X)=根号sin(-2x+π/3)的单调递增区间为

f(x)=√sin(-2x+π/3)=√[-sin(2x-π/3)],其定义域为kπ+2π/3

2kπ<-2x+π/3<2kπ+π/2
2kπ-π/3<-2x<2kπ+π/6
kπ+π/6>x>kπ-π/12