学帮网化简此题
来源：学生作业学帮网 编辑：学帮网 时间：2024/06/21 10:43:05
化简此题
原式=cos2α/[2cot(π/4+α)sin(^2)(π/4+α)]
=cos2α/[2cos(π/4+α)sin(π/4+α)]
=cos2α/sin(π/2+2α)
=cos2α/cos(2α)=1
原式=cos2α/[2cot(π/4+α)sin(^2)(π/4+α)]
=cos2α/[2cos(π/4+α)sin(π/4+α)]
=cos2α/sin(π/2+2α)
=cos2α/cos(2α)=1