已知X²+2X-4=0,求2（X-1）²-X(X-6)+3的值想了半天,求步骤和式子,顺便讲讲,

已知X²+2X-4=0,求2（X-1）²-X(X-6)+3的值
想了半天,求步骤和式子,顺便讲讲,

答：
x²+2x-4=0
2(x-1)²-x(x-6)+3
=2x²-4x+2-x²+6x+3
=x²+2x+5
=x²+2x-4+9
=0+9
=9