若角A,B满足-π/2

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若角A,B满足-π/2

因为 -π/2 < B < π/2
所以 -π/2 < -B < π/2
因为 -π/2 < A < π/2
所以 -π< A - B < π
因为 A < B
所以 A - B < 0
所以 -π< A - B < 0

若角A,B满足-π/2 若角A、B满足-π/2 若角A、B满足-π/2 若角a,b满足-π/2 若角a,b满足-π/2 若角A、B满足-π/2 若角A、B满足-π/2 若角A,B满足-π/2 若角A、B满足-π/2 若角A.B满足-π/2-π/2- 若角a,b满足-∏/2 若角a,b满足-派/2 若角a,b满足-90 若角a,β 满足 -π/2 已知a,b满足-派/2 设a,b满足-(pai/2) a,b满足0 a,b满足0