先化解,后求值:(a+1份之1+a-1份之1)÷a²-2a+1份之2a,其中a=2

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先化解,后求值:(a+1份之1+a-1份之1)÷a²-2a+1份之2a,其中a=2

[1/(a+1)+1/(a-1)]÷2a/(a-1)^2
=2a/(a^2-1)÷2a/(a-1)^2
=2a/(a^2-1)*(a-1)^2/2a
=a-1
=1