(log2 3+log4 9.+log8 27+.+log(2^n底)(3^n))log9 n次根号32恩...是n次根号,,是小n,在左上角的 5

来源：学生作业学帮网 编辑：学帮网 时间：2024/06/04 07:44:10

(log2 3+log4 9.+log8 27+.+log(2^n底)(3^n))log9 n次根号32
恩...是n次根号,,是小n,在左上角的 5

只要使用公式
log(a^n底)(b^m))=m/n*loga b
(log2 3+log4 9.+log8 27+.+log(2^n底)(3^n)这些相加的项都是相等的
还有就是log2 3=1/log3 2

(log2 3+log4 9.+log8 27+....+log(2^n)(3^n))log9 n√32

log4 243 - log8 729=?log4 12 - log2 6=? 求值：(log4(3)+log8(3))(log3(2)+log3(4))-log2(64) log8(9)*log2(3) 计算（log2 3+log4 9+log8 27+……+log2^n 3^n）log9 n次根号3计算（log2 3+log4 9+log8 27+……+log2^n 3^n）log9 n次根号32 log3^36-log3^4+log2(log2^16)+8^2/3+(27/8)^-1/3+log8^27/log4^9怎么算啊,不好意思哦,我已经没分啦.麻烦一下写一写log2(log2^16) (27/8)^-1/3 log8^27/log4^9 化简：（log2(3)+log4(9)+log8(27)+…+log2n(3^n))*log2(8的n次方根) (log2 3+log4 9+log8 27+...+log2^n 3^n）log9 32的N次方根 (log2 3+log4 9+log8 27+...+log2^n 3^n）log9 32的N次方根 (log4＾3+log8＾3)(log3＾2+log9＾2)+log2＾(32)的1/4次方 log4(3)+log8(3) 怎么算 log4(3)+log8(3) 怎么相加? (log4(3)+log8(3))*log3(2) (log8 9/log2 3)=? 求(log2^3+log8^9) log4 3和log8 3是通过哪条法则转换成（1/2)log2 3和（1/3)log2 3的? 求值：【log2（3）+log4（9）+log8（27）+log16（81）+log32（243）】—5log2（3/2) [log2 (125) +log4(25)+log8(5)][log125(8)+log25(4)+log5(2)][log2 (125) +log4(25)+log8(5)][log125(8)+log25(4)+log5(2) (log2 3+log4 9.+log8 27+.+log(2^n底)(3^n))log9 n次根号32恩...是n次根号,,是小n,在左上角的 5