对于等式y=⅓x+6,x满足条件时,y>4;y₁=x+3,y₂=-x+1.当y₁>2y₂时,x满足条件:__

对于等式y=⅓x+6,x满足条件时,y>4;y₁=x+3,y₂=-x+1.当y₁>2y₂时,x满足条件:__

由已知得 1/3x+6>4----------①
x+3>2(-x+1)－－－－－②
由①得 x>-6
由②得 x>-1/3
∴ x>-1/3