一个等腰三角形,周长是35米,腰是底的3/2,这个三角形的面积是多少平方米
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一个等腰三角形,周长是35米,腰是底的3/2,这个三角形的面积是多少平方米
设底为a,则腰为3a/2,依题意有:
a+2*3a/2=35,解之得 a=35/4米,
三角形的面积=√[35/2*(35/2-35/4)*(35/2-3/2*35/4)*(35/2-3/2*35/4)]=54.1379平方米
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