已知三角形ABC是等边三角形,AE=CD,AD与BE相交与P,BQ垂直QD,垂足是点Q,求证BP=2PQ

已知三角形ABC是等边三角形,AE=CD,AD与BE相交与P,BQ垂直QD,垂足是点Q,求证BP=2PQ

见图

即证 角PBQ=30度
设BQ延长角AC与F
因为设那么因为所以因为所以所以得证

图呢！

Correction factor for magnetic bearings fuzzy control,abercrombie paris ouverture


Chinese Abstract: Active magnetic bearing their own characteristics and performance needs,franklin ...

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Correction factor for magnetic bearings fuzzy control,abercrombie paris ouverture


Chinese Abstract: Active magnetic bearing their own characteristics and performance needs,franklin marshall pas cher, propose a correction factor for fitting fuzzy controller design method. 4 using the simplex method for the correction factor of four fuzzy controller to optimize the correction factor to make the improved minimum ITAE performance index. Correction factor in the fitting fuzzy controller,abercrombie france, using a third-order polynomial for the four optimized correction factor for the use of least squares approximation. And no longer on the quantification of inputs and outputs. Simulation results show that the fuzzy controller fitted correction factor can be well controlled,birkenstock paris, effectively improving the dynamic performance of magnetic bearings and steady-state performance.
fuzzy control of active magnetic bearings fitted correction factor correction factor

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因为AB=AC,AE=CD,∠BAE=∠ACD=60度
所以△BAE与△ACD是全等三角形
则：∠ABE=∠CAD
又∠AEB=∠PEA
所以：△BAE与△APE是相似三角形
则：∠APE=∠BAE=60度
所以：∠APE=∠BPQ=60度
则在Rt△BPQ中，∠PBQ=30度
因为：sin∠PBQ＝PQ/BP=1/2

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因为AB=AC,AE=CD,∠BAE=∠ACD=60度
所以△BAE与△ACD是全等三角形
则：∠ABE=∠CAD
又∠AEB=∠PEA
所以：△BAE与△APE是相似三角形
则：∠APE=∠BAE=60度
所以：∠APE=∠BPQ=60度
则在Rt△BPQ中，∠PBQ=30度
因为：sin∠PBQ＝PQ/BP=1/2
所以：BP=2PQ

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