sin(π/8)四次方+cos(π/8)四次方等于?

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sin(π/8)四次方+cos(π/8)四次方等于?

=[sin(π/8)二次方+cos(π/8)二次方]^2 - 2·sin(π/8)二次方·cos(π/8)二次方
=1 - (1/2)·sin(π/4)二次方
=1 - (1/2)·(√2/2)二次方
=3/4