学帮网计算:[(x^2 - 4)/(x^2 - x - 6) + (x+2)/(x-3)] / (x+1)/(x-3)
来源：学生作业学帮网 编辑：学帮网 时间：2024/04/29 06:58:40
计算:[(x^2 - 4)/(x^2 - x - 6) + (x+2)/(x-3)] / (x+1)/(x-3)
[(x^2 - 4)/(x^2 - x - 6) + (x+2)/(x-3)] / (x+1)/(x-3)
=[(x+2)(x-2)/(x-3)(x+2)+(x+2)/(x-3)] /(x+1)/(x-3)
=[(x-2)/(x-3)+(x+2)/(x-3)] /(x+1)/(x-3)
=2x/(x-3)/(x+1)/(x-3)
=2x/(x+1)
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