A compound contains only carbon,hydrogen,and oxygen.Combustion of 10.68 mg of the compound yields 16.01 mg CO2 and 4.37 mg H2O.The molar mass of the compound is 176.1 g/mol.What are the empirical and molecular formulas of the compound?(Type your answ
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A compound contains only carbon,hydrogen,and oxygen.Combustion of 10.68 mg of the compound yields 16.01 mg CO2 and 4.37 mg H2O.The molar mass of the compound is 176.1 g/mol.What are the empirical and molecular formulas of the compound?(Type your answer using the format CO2 for CO2.)
empirical formula
_____________
molecular formula
_____________
n(C)=0.01601/44=3.64*10^(-4)mol
n(H)=0.00437/18*2=4.86*10^(-4)mol
n(O)=[m(总)-m(H)-m(C)]/M(O)=3.64*10^(-4)mol
n(化合物)=0.01068/176.1=0.61*10^(-4)mol
n(化合物):n(C):n(H):n(O)
=1:6:8:6
分子式为:C6H8O6
一种化合物只含有碳,氢,氧。燃烧10.68毫克的化合物产生16.01毫克的二氧化碳和4.37毫克的水。这种化合物的摩尔质量为176.1克/ mol的。这种化合物的经验式和分子式各是? (答案的格式请参照co2) 。
经验式
_____________
分子式
A compound contains only carbon,hydrogen,and oxygen.Combustion of 10.68 mg of the compound yields 16.01 mg CO2 and 4.37 mg H2O.The molar mass of the compound is 176.1 g/mol.What are the empirical and molecular formulas of the compound?(Type your answ
compound
compound
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