【提公因式法】练习解答⑴x(x-y)(a-b)-y(y-x)(b-a)本来想打很多题..可不会符号..

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【提公因式法】练习解答
⑴x(x-y)(a-b)-y(y-x)(b-a)
本来想打很多题..
可不会符号..

原式=(a-b)(x-y)^2

原式=x(x-y)(a-b)-y(x-y)(a-b)
=(x-y)^2(a-b)

x(x-y)(a-b)-y(y-x)(b-a)
=x(x-y)(a-b)-y(-x+y)(-a+b)
=x(x-y)(a-b)-y*-(x-y)*-(a-b)
=x(x-y)(a-b)-y(x-y)(a-b)
=(x-y)(x-y)(a-b)
=(a-b)乘以(x-y)的平方

x(x-y)(a-b)-y(y-x)(b-a)
=x(x-y)(a-b)-y(-x+y)(-a+b)
=x(x-y)(a-b)-y*-(x-y)*-(a-b)
=x(x-y)(a-b)-y(x-y)(a-b)
=(x-y)(x-y)(a-b)

x(x-y)(a-b)-y(y-x)(b-a)
=x(x-y)(a-b)-y(x-y)(a-b)
=(a-b)(x-y)^2