计算:(5-xy/x^3-x^2y)/(1-5/xy)^2*(y-x)^3

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计算:(5-xy/x^3-x^2y)/(1-5/xy)^2*(y-x)^3

(5-xy/x^3-x^2y)/(1-5/xy)^2*(y-x)^3
=-(x-y)^3[-(xy-5)/x^2(x-y)]/[(xy-5)/xy]
=(x-y)^3(xy-5)xy/x^2(x-y)(xy-5)
=y(x-y)^2/x

让我想两会啊

让我想一会啊

(5-xy/x^3-x^2y)/(1-5/xy)^2*(y-x)^3
=[(5-xy)/x^2(x-y)]/[(xy-5)/xy]^2*(y-x)^2
=(5-xy)/x^2(x-y)*(xy)^2/(xy-5)^2*(y-x)^2
=y^2(x-y)/(5-xy).