已知x分之1减y分之1等于7,求(x方+y方)除以xy

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已知x分之1减y分之1等于7,求(x方+y方)除以xy


1/x-1/y=7
(y-x)/xy=7
y-x=7xy
∴(x²+y²)/xy
=[(x-y)²+2xy]/xy
=[(y-x)²+2xy]xy
=(49xy+2xy)/xy
=(51xy)/xy
=51