1/2log2(7/48)+log2 12-1/2log2 42log2 的2 在g的右下脚
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1/2log2(7/48)+log2 12-1/2log2 42
log2 的2 在g的右下脚
原式=log2[√(7/48)]+log2(12)-log2(√42)
=log2[√(7/48)×12÷√42]
=log2[√(144/6×48)]
=log2[√(1/2)]
=log2[2^(-1/2)]
=-1/2
原式=1/2log2 (7/48)+1/2log2 (12*12)-1/2log2 42
=1/2log2 [(7/48)*(12*12)/42]
=1/2log2 1/2
=1/2*(-1)
=-1/2
loga(b)+loga(c)=loga(b*c)
2loga(b)=loga(b^2)
题目=log2(根号下((7/48)*144*42))=1/2log2(882)
1楼2楼正解,最主要的是把公式记住,同底对数提公因式,加变乘,减变除,前面的系数相应提进去变指数。把书上公式记好,剩下就是些运算了。
log2 SQR(7/48)+log2 12 -1/2log2 48
log2 SQR(7/48)+log2 12 -1/2log2 42
1/2log2(7/48)+log2 12-1/2log2 42log2 的2 在g的右下脚
化简算式log2^√7/48+log2^12-1/2log2^42+1/2^log2^3
log2(根号下7/48)+log2(12)-1/2log2(42)-1=?
log2根号7/48+log2^12-1/2log2^42-1=
求值:log2√(7/48)+log2(12)-1/2log2(42)-1 这道题我算来算去算不对
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