a(a+b)-[0.5a*a-0.5(a+b)b-0.5b(a-b)]

来源：学生作业学帮网编辑：学帮网时间：2024/06/11 09:36:41

原式=a²+ab-(0.5a²-0.5ab-0.5b²-0.5ab+0.5b²)
=a²+ab-(0.5a²-ab)
=a²+ab-0.5a²+ab
=0.5a²+2ab

a(a+b)-[0.5a*a-0.5(a+b)b-0.5b(a-b)]
=a²＋ab-0.5(a²-ab-b²-ab+b²)
=a²＋ab-0.5×a²+ab
=0.5a²＋2ab

a(a+b)-[0.5a*a-0.5(a+b)b-0.5b(a-b)] a-b>a,a+b (a+b).(a-b) a/b-b/a a+b>a-b, A*b/a>A ,那么a/b A b a a 成语先化简再求值(a-b/a+b)+(a+b/a-b)-（2a²-2b²/a²+b²）其中a=-2,b=0.5 a,b,c(a return a>b?a: (a-b)(a-三分之一) a>b,a (a,b)与a a a a a a