计算题如图,该怎么算?
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计算题如图,该怎么算?
4a/(a^2-1)-(a+1)/(a-1)
=4a/(a^2-1)-(a+1)^2/[(a-1)*(a+1)]
=(4a-a^2-2a-1)/(a^2-1)
=-(a-1)^2/(a^2-1)
=-(a-1)/(a+1)
4a/(a^2-1)-(a+1)/(a-1)
=4a/(a^2-1)-(a+1)^2/[(a-1)*(a+1)]
=(4a-a^2-2a-1)/(a^2-1)
=-(a+1)^2/(a^2-1)
1/4a的平方-4a
-(a-1)/(a+1)
4a/a*a-1
=(1-a)/(a+1)