dy/dx-2+y/x=0的通解是什么?

来源：学生作业学帮网编辑：学帮网时间：2024/06/06 10:23:02

∵dy/dx-2+y/x=0
==>dy-2dx+ydx/x=0
==>xdy-2xdx+ydx=0
==>(xdy+ydx)-2xdx=0
==>d(xy)-d(x^2)=0
==>xy-x^2=C (C是常数)
==>x(y-x)=C
∴原方程的通解是x(y-x)=C.