先化简,在求值:[x(X-y)-y(x-y)+(x+y)(x-y)]除2x,其中x=2012,y=2013

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先化简,在求值:[x(X-y)-y(x-y)+(x+y)(x-y)]除2x,其中x=2012,y=2013

[x(X-y)-y(x-y)+(x+y)(x-y)]除2x
=(X²-xy-xy+y²+x²-y²)除2x
=(2x²-2xy)÷2x
=x-y
=2012-2013
=-1