a(x-y)^2n-b(y-x)^2n+1(分解因式)还有几题 好心人帮我一起回答了吧:(a-b)²(a+b)³-(b-a)²(b+a)² 2(a-b)²-a+b -x²(m-n)^5-xy(n-m)³ 35ab(x-y
来源:学生作业学帮网 编辑:学帮网 时间:2024/05/28 23:46:58
a(x-y)^2n-b(y-x)^2n+1(分解因式)
还有几题 好心人帮我一起回答了吧:(a-b)²(a+b)³-(b-a)²(b+a)² 2(a-b)²-a+b -x²(m-n)^5-xy(n-m)³ 35ab(x-y)²-25a²b²(y-x)²+10ab³(y-x)³ (都是分解因式)
a(x-y)^2n-b(y-x)^2n+1
=a(y-x)^2n-b(y-x)^2n+1
=(y-x)^2n*(a-by+bx)
(a-b)²(a+b)³-(b-a)²(b+a)²
=(a-b)²(a+b)²(a+b-1)
2(a-b)²-a+b
=(a-b)(2a-2b-1)
-x²(m-n)^5-xy(n-m)³
=-x²(m-n)^5+xy(m-n)³
=-x(m-n)³[x(m-n)²-y]
=-x(m-n)³(xm²-2mnx+xn²-y)
35ab(x-y)²-25a²b²(y-x)²+10ab³(y-x)³
=5ab(x-y)²(7-5ab-2bx+2by)
(x+y+z)^2-(x-y-z)^2(a-b)^n+2 -(a-b)^n
y^2-9(x+y)^2.a(x-y)-b(y-x)+c(x-y)..x(m+n)-y(n+m)+(m+n)..(x+y)^2-16(x-y)^2因式分解
m(x-y)^n+n(y-x)^2n因式分解
已知a,b,x,y都是实数,n∈N,x+yi=(a+bi)^n,求证:x^2+y^2=(a^2+b^2)^n
因式分解:a(x-y)的n次方-3b(y-x)的n+1次方+2c(y-x)的n+2次方(n为正整数)
A={y|y=x2-4x+6,y属于N},B={y|y=-x2-2x+18,y属于N},求A交B.
假设集合U={(x,y)|x∈R,y∈R },A={(x,y)|2x-y+m>0},B={(x,y)|x+y-n
x^n*y*(-x^2y^m)
x^2y(a-b)^2n+xy^2(b-a)^2n+1因式分解
分解因式:x(a-b)2n次方+y (b-a)2n+1次方
x(a-b)*2n+y(b-a)*2n-1 怎么因式分解,
x(a-b)的2n次方+y(b-a)的2n-1次方=?
因式分解 ;(x-y)平方-(y-x)平方 a(x-y)n次方-3b(y-x)n+1次方+2c(y-x)n+2次方(n为正整数)
12xy(m-n)-x的平方(n-m)的平方x(x-2y)(a-b)-y(2y-x)(b-a)、、、、、、、、、、?
matlab利用递归求解差分方程function y = recur(a,b,n,x,x0,y0);%% y = recur(a,b,n,x,x0,y0)% solves for y[n] from:% y[n] + a1*y[n-1] + a2*y[n-2]...+ an*y[n-N]% = b0*x[n] + b1*x[n-1] + ...+ bm*x[n-M] %% a,b,n,x,x0 and y0 are vectors% a = [a1 a2
y-n = - (a-m)(x-m)/(b-n) .(1) (x-m)^2+(y-n)^2 = L^2 .(2) 求X,Y的值
若n是正整数,有理数x、y满足x+y分之一=0,则一定成立的是 A.x^2n+1+(1/y)^n=0 B.x^2n+1+(1/y)^2n+1=0C.x^2n+(1/y)^2n=0 D.x^n+(1/y)^2n=0
y=x^2/(a^2-b^2 *x^2) 求y的n阶导数