1/2(m+1)-1/3(2m-1+1/6(m-5)

1/2(m+1)-1/3(2m-1+1/6(m-5)

原式=1/2m+1/2-2/3m+1/3+1/6m-5/6
=(1/2-2/3+1/6)m+(1/2+1/3-5/6)
=0

=1/2m+1/2-2/3m+1/3+1/6m-5/6
=(1/2-2/3+1/6)m+(1/2+1/3-5/6)
=01.5a²-[3a-2（2a-3）-4a²] 2.化简求值：1/2a-2（a-1/3b²）+（-3/2a+1/3b²） a=2 b=2/3 3.已知（a+2）²+|a+b+5|=0，求3a
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=1/2m+1/2-2/3m+1/3+1/6m-5/6
=(1/2-2/3+1/6)m+(1/2+1/3-5/6)
=0

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