定义新运算e为xey=2xy-(x+y),求12e(3e4)

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定义新运算e为xey=2xy-(x+y),求12e(3e4)

3e4
= 2*3*4 - (3 + 4)
= 24 - 7
= 17
12e(3e4)
= 12 e 17
= 2*12*17 - (12 + 17)
= 408 - 29
= 379

3e4=2*3*4-3-4=17
12e(3e4)=2*12*7-12-7=159

因为:xey=2xy-(x+y)
所以:3e4=2×3×4-(3+4)
=24-7
=17
12e(3e4)
=12e17
=2×12×17-(12+17)
=408-29
=379